58 lines
3.3 KiB
Markdown
Executable File
58 lines
3.3 KiB
Markdown
Executable File
| Temperature | Skin | Blood Pressure | Blocked Nose | Diagnosis |
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| ----------- | ------ | -------------- | ------------ | --------- |
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| Low | Pale | Normal | True | N |
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| Moderate | Pale | Normal | True | B |
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| High | Normal | High | False | N |
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| Moderate | PaleFF | Normal | False | B |
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| High | Red | High | False | N |
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| High | Red | High | True | N |
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| Moderate | Red | High | False | B |
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| Low | Normal | High | False | B |
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| Low | Pale | Normal | False | B |
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| Low | Normal | Normal | False | B |
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| High | Normal | Normal | True | B |
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| Moderate | Normal | High | True | B |
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| Moderate | Red | Normal | False | B |
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| Low | Normal | High | True | N |
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| | Temperature | | | Skin | | | Pressure | | | Blocked | | Diag | |
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| -------- | ----------- | --- | ------ | ---- | --- | ------ | -------- | --- | ----- | ------- | --- | ---- | ---- |
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| | N | B | | N | B | | N | B | | N | B | N | B |
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| Low | 2 | 3 | Pale | 1 | 3 | Normal | 1 | 6 | True | 3 | 3 | 5 | 9 |
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| Moderate | 0 | 5 | Normal | 2 | 4 | High | 4 | 3 | False | 2 | 6 | | |
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| High | 3 | 1 | Red | 2 | 2 | | | | | | | | |
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| | Temperature | | | Skin | | | Pressure | | | Blocked | | | Diag |
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| Low | 2/5 | 3/9 | Pale | 1/5 | 3/9 | Normal | 1/5 | 6/9 | True | 3/5 | 3/9 | 5/14 | 9/14 |
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| Moderate | 0/5 | 5/9 | Normal | 2/5 | 4/9 | High | 4/5 | 3/9 | False | 2/5 | 6/9 | | |
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| High | 2/5 | 1/9 | Red | 3/5 | 2/9 | | | | | | | | |
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# Problem 1
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# $Pr[Diagnosis=N|E] = \frac{2}{5} \times \frac{2}{5} \times \frac{4}{5} \times \frac{3}{5} \times \frac{5}{14} = 0.027428571$
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# $Pr[Diagnosis = B|E] = \frac{3}{9} \times \frac{4}{9} \times \frac{3}{9} \times \frac{3}{9} \times \frac{9}{14} = 0.010582011$
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# $p(B) = \frac{0.0106}{0.0106+0.0274} = 0.2789$
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# $p(N) = \frac{0.0274}{0.0106+0.0274} = 0.7211$
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Diagnosis N is much more likely than Diagnosis B
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# Problem 2
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# $Pr[Diagnosis = N|E] = \frac{2}{5} \times \frac{1}{5} \times \frac{3}{5} \times \frac{5}{14} = 0.0171$
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# $Pr[Diagnosis = B|E] = \frac{3}{9} \times \frac{6}{9} \times \frac{3}{9} \times \frac{9}{14} = 0.0476$
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# $p(N) = \frac{0.0171}{0.0171+0.0476} = 0.2643$
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# $p(B) = \frac{0.0474}{0.0476+0.0171} = 0.7357$
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Diagnosis B is much more likely than Diagnosis N
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# Problem 3
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# $Pr[Diagnosis = N|E] = \frac{0}{5} \times \frac{2}{5} \times \frac{4}{5} \times \frac{3}{5} \times \frac{5}{14} = 0$
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# $Pr[Diagnosis = B|E] = \frac{5}{9} \times \frac{4}{9} \times \frac{3}{9} \times \frac{3}{9} \times \frac{9}{14} = 0.018$
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